need helppp!

Calc 3 question: An irrigation canal has the shape of a trapazoid. Let x =the bottom width, y =the water depth, and theta=the angle of inclination of the sides from the vertical. Area=A=y(x+ytan(theta)) and Perimeter=P=x+2y/cos(theta) It is known that the best design for a fixed inclination is found by minimizing Perimeter subject to the constraint that the area A = Ao is constant. Show that this implies that y^2 = Ao*cos(theta)/(2-Sin(theta))

Question

need helppp!

Calc 3 question: An irrigation canal has the shape of a trapazoid. Let x =the bottom width, y =the water depth, and theta=the angle of inclination of the sides from the vertical. Area=A=y(x+ytan(theta)) and Perimeter=P=x+2y/cos(theta) It is known that the best design for a fixed inclination is found by minimizing Perimeter subject to the constraint that the area A = Ao is constant. Show that this implies that y^2 = Ao*cos(theta)/(2-Sin(theta))

anonymous · Answer

I understand how to get the perimeter and area equations but not sure how to get y^2 = Ao*cos(theta)/(2-Sin(theta))

anonymous · Answer

i'll take a look at that brass - be back soon

anonymous · Answer

cool thanks

anonymous · Answer

sorry guy - no inspiration- and i have to go

anonymous · Answer

its alright i appreciate the effort