find an equation of the line through the pair points. write the eqaution in the form Ax+By=C

(-6,3) and (4,0)

Question

find an equation of the line through the pair points. write the eqaution in the form Ax+By=C

(-6,3) and (4,0)

myininaya · Answer

y=mx+b
we can find m
$$m=\frac{3-0}{-6-4}=\frac{3}{-10}=-\frac{3}{10}$$
we can find b we know m and we know a x and a y (x,y)=(4,0)
$$0=-\frac{3}{10}*4+b$$
$$0=\frac{-12}{10}+b$$
$$b=\frac{12}{10}=\frac{6}{5}$$
$$y=\frac{-3}{10}*x+\frac{6}{5}$$
now lets write it in the form Ax+By=C
$$10y=-3x+12$$
$$3x+10y=12$$

anonymous · Answer

m = (y1-y2) / (x1-x2)
    = (3-0)/(-6-4)
    = 3/-10
m= -3/10

y = -3/10x + c
3 = -3/10(-6) + c   ...substitute in and solve for C
3 = 18/10 + c   
c = 3 - 18/10
c = (30-18)/10
c = 12/10

y = -3/10x + 12/10 multiply all by 10
10y = -3x + 12

therefore 3x + 10y = 12