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∫x^xdx
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=x^3/3
NOPE
x^x+1\x+1
\[∫x^{x}\]
oops sorry...i mistook it for x^2 sorry
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lets see whose smart, thats ntot right either
yea it is if it was x^2
but its x^x
git the point now...
got*** And i have no idea how to solve it...:)☺
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Don't exist.
me either i know how to take its derivitive but i think you need to get super creative with it like ∫e^-x^2
"(no result found in terms of standard mathematical functions)" -> It doesn't. Reference : http://mathworld.wolfram.com/PowerTower.html , eqn (27)
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