Question

Why is the Vertical Asymptote x=(-1) for
f(x)= -1/(x+2)^2
Shouldn't it be x=(-2) since (x+2)^2 = (x+2)(x+2) and x+2=0 becomes x=(-2)?

Answer 1

you are right.

Answer 2

your function is not defined at x = -2, and that is the vertical asymptote. horizontal is
\[y=0\]