Question

Given segment AM as the perpendicular bisector in the equilateral triangle ABC, which statement is true?
BM + CM = 2AM
AB + BC = 4AM
2BM + 2CM = 2AB
2BM + 3CM = 5AB
.

Answer 1

bm + cm = ab; am = sqrt(3)/2; bm=1; cm=1; i wonder

Answer 2

Since AM is the perpendicular bisector of the equilateral triangle, M should divide the line BC in half. Thus BM = CM, and BM + CM = BC. Thus, 2BM + 2CM = 2(BM + CM) = 2BC, and since the triangle is equilateral, 2BC = 2AB. Thus, the third option is correct.

Answer 3

ab would equal say 2; ab + bc = 4; sqrt(3/2)*4 not the same

Answer 4

i believe its the 3rd one. 2(BM + CM) = 2(AB)

Answer 5

thank you :)

Answer 6

i agree with the third one since we have 2BM+2MC=2*x/2+2*x/2=x+x=2x=2(AB)

Answer 7

where x is length of BC and AB and AC