Question

how would i go about finding max and min of y=(x-1)^2(x+1)^2

Answer 1

take the first derivative and set it equal to 0..

Answer 2

then solve for all xs

Answer 3

And suppose you get these values... x=x1, x=x2, x=x3, etc... where x1 x2 and x3, etc.. are the answers to the quadratic equation u are going to get from y'
So once you have all of those answers, take the second derivative, or find y"

Answer 4

would i have to use the chain rule in this case?

Answer 5

Thaanks, same process for y=3-(x-1)^2/3

Answer 6

how about y=3-(x-1)^2/3, is it the same process?

Answer 7

yes you can also find the second to find max and min
so you would get y''=4(3x^2-1) for the first one
y''(-1)=+=> min at x=-1
y''(0)=- => max at x=0
y''(1)=+=> min at x=1