Solve this system of equations using substitution. a+b+c=180 b=3a c=5a b=?
Have you tried it yet?
need help please!!!
How far did you get?
thats eassy just substitute for a & c then get b
i dont know where to start
Plug in b=3a and c=5a into a+b+c=180. Solve this for a. When you know a, you can easily solve b=3a for b.
can you show me the step for this question?
Sure. Since b=3a and c=5a, when we substitute these values into a+b+c=180, we get a+3a+5a=180. So 9a+180. Therefore, a=20. Does that make sense? Now you plug the value for a into the equation b=3a. What do you get for b then?
simply replace b = 3a and c = 5a to get b then you can continue from there easy enough
is it b=60
Yep. Good job.
plug it in and see
You can check your work by plugging in a=20, b=3a=3(20)=60, and c=5a=5(20)=100 into a+b+c=180 and making sure that it works (which it does).
I need help on C=5a
you have what a equals and you have what b equals put them together in your intial equation and check to see if it works.
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