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write as a single log log(x-1)+log2-(1/2logx)
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\[ \log((x-1)+100-x ^{1/2})\]
how did you get 100
oh right base 10^2
loga + logb = logab loga - logb = log a/b log a^n = nlog a use these rules to get \[=\log_{}\frac{2(x-1)}{\sqrt{x}} \]
dumbcow is correct
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sinceits addition you multiply amd subtraction you divide i am wrong
thats correct thanks guys
i have another one posted maybe you could help =)
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