the perimeter of a rectangular is 162 m . the length is 9m more then twice the width find the dimensions. what is the length?

Question

blacksteel · Answer

I posted this in your other post with the same question, but in case you're looking here:

The perimeter is twice the length plus twice the width. If the length is L and the width is W, the perimeter P is P = 2W + 2L. we also know that P = 162, so 2W + 2L = 162.

We know that the length is twice the width + 9, so L = 2W + 9.

Then we can substitute this answer into the perimeter equation to get 2W + 2(2W + 9) = 162. Simplifying this gives us 6W + 18 = 162, or 6W = 144. Dividing both sides by 6 gives us W = 24.

Since we now know W, we can substitute this back into our second equation, L = 2W + 9. This gives us L = 2(24) + 9, or L = 57.

(Saifoo's technique was correct, but the problem reads that the length is twice the width + 9, not the width + 9.)

anonymous · Answer

i give up on this questions

anonymous · Answer

P=(L+W)2
L=9+2W
162=((9+2W)+W))2
162=(9+3W)2
162=18+6W
162-18=6W
144 /6=W
24 = Width
length = 9 +2(24)
          =9+48
length = 57

anonymous · Answer

From the diagram:

$$6w + 18 = 162 \rightarrow w = \frac{144}{6} = 24$$

so 

$$l = 2w + 9  = 57$$