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how do I find the x and y intercepts of f(x) = -2(x-3)(x-3) +1
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if u want to find the x-intercept u put y=0 and if u want to find the y-intercept u put x=0
for the y intercept let x=0 then solve for y -2(-3)(-3)+1 -18+1 -17
for the x intercept you have to foil the polynomials first then distribute the -2 then add 1 -2(x^2-6x+9)+1 -2x^2+12x-18+1 -2x^2+12x-17 Then use the method best suited for you in order to factor this down
i like to use the box method, less confusing less to worry about
for y=0 you get \[x=3\pm \sqrt{2}\div2\]
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in this case box method is not the best but rather the quadratic formula
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