Question

System of Linear equations:
I added y=2x-8 to -3y+10=2
and I got -2y=2x+16.. I know I did something wrong- HELP!

Answer 1

do you perhaps mean
\[y=2x-8\]
\[-3y+10x=2\]?

Answer 2

if so replace y in the second equation by 2x-8.
if not then i am not sure what the question is

Answer 3

ok, we already know y, it is 8/3

we just need to find where x intersects that point

it is 8/3=2x-8

isolate x from here...

Answer 4

@ frownupsidedown what is the actual problem?

Answer 5

he needs the point where the two lines intersect

Answer 6

Solve the system of linear system equations by any method of choice
y=2x-8 &
-3y+10=2

Answer 7

is the second equation
\[-3y+10=2\] with no x in it?

Answer 8

It is a horizontal line

Answer 9

if so Llort is right

Answer 10

Correct. That's probably why I'm so confused :P

Answer 11

\[-3y+10=2\]
\[-3y=-8\]
\[y=\frac{8}{3}\] a horizontal line. then replace y by
\[\frac{8}{3}\] in other equation to find x

Answer 12

what Llor said. i thought maybe you had made a typo but second equation just fixes y at 8/3 and go from there

Answer 13

@Llort sorry t doubt you

Answer 14

not a problem

Answer 15

Ohhh, Okay! Thank you so much! I get it now

Answer 16

glad I could help