Question

5 sqrt of 93

Answer 1

do you mean the fifth root of 93

Answer 2

2.4756918656443665097464962340518985001370237906844844328382...

Answer 3

Yes

Answer 4

2.47569 should sufffice

Answer 5

but that is not fun...

Answer 6

48.218

Answer 7

or is it 5*sqrt(93)?

Answer 8

same thing. :P

Answer 9

lol.

Answer 10

in that case...

48.218253804964774978800155237163315919534518465316262036500...

I WIN

Answer 11

that was my first question too she replied saying no..our first assumptions (llort's and mine were correct)

Answer 12

llort :what re you on

Answer 13

haha.

Answer 14

do you want some?

Answer 15

don't take it the wrong way i ment mathematica, maple,octave,matlab,scilab etc :)
(i love phrase puns )

Answer 16

none of those... I do it all with my mind... =P

Answer 17

Can someone explain how this works?

Answer 18

wow some mind..

Answer 19

@becca: use Calc.

Answer 20

+ is to - and * is to / is what sqrt(x) is to ^

Answer 21

sorry..we've taken ober reb's question.
reb:yes use the calculator:otherwise use logs

Answer 22

*over

Answer 23

I was meaning how would you work the problem? Thanks. Just trying to understand this so I will be ready for the test.

Answer 24

\[\sqrt[n]{x} = x^{1/n}\]
so
\[\sqrt[5]{93} = 93^{1/5}\]

Answer 25

say 93^(1/5) = x
take log on both sides...
1/5 * log(93) = logx
you get some number on the left...then take that number's antilog...to regenerate x

Answer 26

Evern, log/antilog. Not sure what that is.

Answer 27

ok

Answer 28

what grade are you in?

Answer 29

Learning Support Algebra. Been out of school for 15 years

Answer 30

all you need to know how to do is use a calculator to find value of
\[93^{1/5}\]
push 93 then the "^" key and then (1/5)

Answer 31

o.k. log is the opposite operation of exponentiation.:
http://en.wikipedia.org/wiki/Logarithms