Question

pls help with this, if r=d/2 find the area of the bigger semi-circle, subtract the area of the smaller semi-circle from it to get the area of the shaded region. 5in 10 in-shaded area

Answer 1

big radius : 10in

small radius : 5 in??

Answer 2

yes

Answer 3

58.9in^2

Answer 4

i need to see work because i had that and my teacher said its wrong

Answer 5

a = pi(r^2)

a = pi(5/2)^2

a = 25/4pi

area larger circle is

a = pi(r^2)

a = pi(10/2)^2

a = pi(5^2)

a = 25pi

larger - smaller = 25pi - 25/4pi =

100/4pi - 25pi = 75pi/4 is wat i got

Answer 6

are the given measurements in Radius or Diamerter?

Answer 7

shenita
area of semi-circle is (pi*r^2)/2
take half the area, you were squaring (r/2)
area of big: (pi*10^2)/2 = 100pi/2 = 50pi
area of small: (pi*5^2)/2 = 25pi/2 = 12.5pi
subtract
50pi - 12.5pi = 37.5pi = 117.81

Answer 8

ook i see thanx