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Factor 81b^6-3d^6=I got (3(27b^6-d^6) what is the correct form to write the answer.
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do you mean to have the equals sign in there?
not I have the answer but I don't have it in the right written form
I'm pretty sure that you can treat 27b^6-d^6 as a difference of squares
Your answer is a good first step, but now you need to apply the sum of two cubes formula I gave you in the last problem.
a3 + b3 = (a + b)(a2 – ab + b2) In this case, a = 27(b^2), and b=-d^2.
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I need to buy the algebra for dummies book :)
completely ignore what i said, totally wrong approach
Sorry, a = 3(b^2)
so it will be (b+3)(b^3-27b-d6)?
Nah, it'd be 3(3(b^2)-d^2)(9b^4 + 3b^2d^2 - d^4).
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oh wow I was way off.
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