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find domain n range y=1/(x-2)??
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Domain = numbers you can put in for x. In this case, if the denominator is 0, the equation will be undefined. So \[x-2\neq0\] \[x\neq2\] Range is your Y values. In this case, we can have any number except 0, because 1 over nothing will ever = 0. So range: \[y\neq0\]
ok got it.thanx..what about..x=(y-1)^2-2??
You need to solve for y, and then do the same analysis. If you solve for y correctly, x will be under a square root sign. Since you can't have anything negative as a square root, this will restrict your domain. Your range will be all positive real numbers, since a square root will never output a negative real number.
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