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Mathematics 9 Online
OpenStudy (anonymous):

solve 5x^2=15, need x= and x-intercepts

OpenStudy (anonymous):

first, divide by 5 x^2=3

OpenStudy (anonymous):

the square root both sides

OpenStudy (anonymous):

x=+/-squareroot 3

OpenStudy (anonymous):

it is both plus and minus because you are taking the square root

OpenStudy (anonymous):

\[x ^{2}=15/5\] \[x=\sqrt{3}\] x intercept is zero . put x=0 in the eqn

OpenStudy (anonymous):

add plus or minus before sq root

jhonyy9 (jhonyy9):

x_1,_2 = +/- radical 3

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