Question

Betty has 10 more dimes than quarters. If she has $3.45, how many coins does she have?

Answer 1

D = Q + 10
25D + 10D = 345, D and Q in cents.

Answer 2

Solve by substitution.

Answer 3

its asking how many dimes and how many quarters

Answer 4

25Q + 10D = 345.

Answer 5

Solving the system
D = Q + 10
10D + 25Q = 345
gives you the number of dimes and the number of quarters.

Answer 6

x=dimes x-10+quarters
.10(x)+.25(x-10)=3.45
10x+25x-250=345
35x=595
x=17
17 dimes and (17-10) quarters -> 17+7=24 total coins