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Mathematics 18 Online
OpenStudy (anonymous):

You meet a man who tells you he has two children. One of his kids walks into the room and it is a boy. What is the probability the other kid is also a boy.

OpenStudy (anonymous):

1/2. Either he's a boy or a girl, so it's a 50/50 chance.

OpenStudy (anonymous):

50%, the gender of one child does not affect the gender of the next.

OpenStudy (anonymous):

both of you are wrong!

OpenStudy (anonymous):

How so?

OpenStudy (anonymous):

let me rephrase the question: if you know someone has 2 children, at least one of which is a boy, what is the probability he has 2 boys?

OpenStudy (anonymous):

1/3

OpenStudy (anonymous):

blam!

OpenStudy (anonymous):

Combinatorics baby.

OpenStudy (anonymous):

25 % boy 75% girl

OpenStudy (anonymous):

not quite.

OpenStudy (anonymous):

He has two children do you started of with two 50/50 chances or 4 chances at 25%

OpenStudy (anonymous):

Sets: {A=boy ,B=boy} {A=girl ,B =boy}{ A=boy, B=girl}, {A =girl, B=girl} Given a child is a boy, we can remove the double girl set, leaving three sets. A=boy, B=boy is thus 1/3.

OpenStudy (anonymous):

OK 4 variations on boy girl we know girl girl can not happen so only 1 of the last 3 can happen so 1/3

OpenStudy (anonymous):

It's counter-intuitive math, but perfectly logical if you work through it, which is why I like it so much.

OpenStudy (anonymous):

it's one of my favorite probability / combinatorics questions because it's so counter-intuitive. If someone has no background in math, you can get in an hour long discussion about why it's not 50%.

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