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evaluate this integrals; ʃ(√t-1/√t)dt,,,can i ask the solution of the answer???plz....tnx...
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write it as two fraction
\[\int \frac{\sqrt{t}-1}{\sqrt{t}}\ dt\]??
\[1 - 1/\sqrt{t}\]
use exponential notation and then the power rule
made it to 2000+ now ;)
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\[1-t^{-1\over 2}\]
ok thank you everyone for answering my question......
\[\int \sqrt{t}-\frac{1}{\sqrt{t}}dt=\int t^{-\frac{1}{2}}-t^{\frac{1}{2}}dt\]
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