Question

Find the absolute maximum and minimum values of f on the given interval.

f(x) = 2x-3x^(2/3) on the interval [-1,3]

Answer 1

so first we find f'(x) = 2- 2x^(-1/3)

then we set it equal to 0 and solve for x

x= 1

then we plug it back into the original function and get
f(1) = -1

then we plug the endpoints into the function and get
f(-1) = -5

f(3) = -0.24

Answer 2

so our maximum is at 1 and our minimum is at -1

Answer 3

you answered your own question

Answer 4

is that correct?

Answer 5

yup

Answer 6

i know...i just wanted to check my answer

Answer 7

thats how you say where the local max and min is?

Answer 8

on the intervals right?

Answer 9

The highest max and lowest min are your absolute max and min. The rest are rel. max and min if there are any.