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Evaluate the limit lim x->1 (sin(x-1))/(x^2+x-2)
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\[\lim_{x \rightarrow 1} \frac{\sin(x-1)}{(x-1)(x+2)}\] \[\lim_{x \rightarrow 1}\frac{\sin(x-1)}{(x-1)}*\frac{1}{(x+2)}\]
\[\frac{1}{3}\]
is this correct?
nope. as x tends to 1, (x-1)=0 and Sin(x-1)=0 the answer is 0
You should have to use L'Hospital Rule, is very useful, is you have 0/0 or inf/inf, you derivate up and down and evaluate the limit wth the result ¨)
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1/3 is indeed the right answer.
we never learned L'hospitals rule...
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