Compute the determinant of the following matrix by expanding as specified. Where i and j are the position indices of the elements of the matrix. The answers in a, b, and c should be the same. [3 4 -9; 2 10 3; 5 -2 6] a) Along the first row: b) Along the second row: c) Along the third row:
Your matrix: \[\begin{bmatrix}3&4&-9\\2&10&3\\5&-2&6\end{bmatrix}\] I will the determinant along the second row, and the other two are identical, and up to you. First, we compute the cofactors along the second row: \[A_{2,1}=(-1)^{2+1}\begin{vmatrix}4&-9\\-2&6\end{vmatrix}=(-1)\left((4)(6)-(-9)(-2)\right)=-6\] \[A_{2,2}=(-1)^{2+2}\begin{vmatrix}3&-9\\5&6\end{vmatrix}=(+1)\left((3)(6)-(-9)(5)\right)=63\] \[A_{2,3}=(-1)^{2+3}\begin{vmatrix}3&4\\5&-2\end{vmatrix}=(-1)\left((3)(-2)-(5)(4)\right)=26\] \[\det(A)=2(-6)+10(63)+3(26)=696\] The other expansions will yield the same result.
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