Consider the following expression: m^3+3m^2-2m+24 _____________________ m^2-m+5 Divide the polynomial in the numerator by the trinomial in the denomiator
do u want me to show you the division?
please... i dont understand these at all
its a bit messy to type thats why i avoided it!!
here goes:
m + 4 ------------------ first divide m^2 into m^3 m^2-m+5 ) m^3+3m^2-2m+24 m^3 - m^2 +5m multiplying m^2 - m + 5 by m -------------- 4m^2 - 7m +24 subtracting & then bringing down the + 24 4m^2 -4m + 20 multiplyimg m^2 - m + 5 by 4 --------------- -3m + 4 subtracting so -3m + 4 is the remainder quotient is m + 4 this takes some practice before you 'get it'.
so it should be wrote: -3m+4 _________ m+4 is this right?
no it can be written a m + 4 + remainder / m^2-m+5 ie m+4 + (-3m+4) / (m^2-m+5)
if u practice these divisions u will will get them - i know they are not easy though heres one to try x^2 - 5x + 7 divided by x - 1. good luck
i just posted another one...
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