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OpenStudy (anonymous):
OpenStudy (anonymous):
that's a little odd, these are sets, not functions...
OpenStudy (anonymous):
fog = {(1,0),(2,10)}
gof = {(2,-7)}
OpenStudy (anonymous):
Evern can u show step by step?
OpenStudy (anonymous):
sure, think of the function like a program ... input of a sort gives ou a certain out put.
So,we look at the first function all possible outputs -7,1,2 (each has a corresponding input) from f.These form the basis for the input of g. but -7 does not exits as input in g.therefore that cannot be part of the net function.1 and 2 on the other hand have different associated outputs in the case of g ..which gives us the net gof output.
Sorry: i htink i mixed up the the labels for the answer i.e. gof <-> fog
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OpenStudy (anonymous):
OpenStudy (anonymous):
fog = {(2,-7)}
gof = {(1,0),(2,10)}
?
OpenStudy (anonymous):
yes,you got it the variables always go through the function on the right first
OpenStudy (anonymous):
the answer is correct?
fog = {(2,-7)}
gof = {(1,0),(2,10)}
?
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
ty
OpenStudy (anonymous):
can u help me one more?
OpenStudy (anonymous):
OpenStudy (anonymous):
sure, but you have to show how you've tried it first before i do anything
OpenStudy (anonymous):
I will send you my work
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OpenStudy (anonymous):
OpenStudy (anonymous):
fog= I'm not sure
gof= doesn't exit
OpenStudy (anonymous):
fog={(3.-3),(2,-3)}?
OpenStudy (anonymous):
is that a -3 in g
OpenStudy (anonymous):
which one?
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OpenStudy (anonymous):
g -2nd term...where'd you go?
OpenStudy (anonymous):
the set o g is {(1,0),(-3,1),(2,1)}
OpenStudy (anonymous):
on the picture
gof= 1 0 domain of f
1 -3 range f, domain g
0 1 1 range g
OpenStudy (anonymous):
fog ={(1,-3),(3,1)(2,1),} which is a function
OpenStudy (anonymous):
why not -3?
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OpenStudy (anonymous):
fog = 1 3 2 domain of g
0 1 1 range g, domain f
1 -3 range f
why not -3?
OpenStudy (anonymous):
ahhh...you've accidently written 3 on the left hand side fog column
OpenStudy (anonymous):
yes
fog = 1 -3 2 domain of g
0 1 1 range g, domain f
1 -3 range f
than, I think only {(2,1)?
OpenStudy (anonymous):
why both 2 and 3 produce the same output
OpenStudy (anonymous):
2 and -3
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OpenStudy (anonymous):
fog =(2,-3)?
OpenStudy (anonymous):
valid inputs for fog 1->0->-3 , 2->1->1 ,-3 ->1 ->1
OpenStudy (anonymous):
oK, ty
OpenStudy (anonymous):
how gof ?
OpenStudy (anonymous):
gof= 1 0 domain of f
1 -3 range f, domain g
0 1 1 range g
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OpenStudy (anonymous):
gof={(1,0),(0,1)}
OpenStudy (anonymous):
ty
OpenStudy (anonymous):
your welcome...what grade are you in
OpenStudy (anonymous):
*you're
OpenStudy (anonymous):
algebra 2
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OpenStudy (anonymous):
so the 11th or 12th
OpenStudy (anonymous):
12th, r u teacher?
OpenStudy (anonymous):
no...i.m a student myself
OpenStudy (anonymous):
u r smart , bye
OpenStudy (anonymous):
thanks ,see you if you have any more questions fb me.
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