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vertices @ saifoo.khan
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ok trutfully idk what to do after that do you?
IM here.
lol, Ok. Let me try to help. till where u got that ques?
right where we stopped when you said to use pythagoras and i was like and do what?
Give me those Lengths which u got.
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A= (2,1) , B = (4,0) , C= ( 5, 7 )
sqrt{5}, 5sqrt{2}, 3sqrt{5}
Label them.
ok, which one is Pythagoras?
AB= sqrt(5) , BC= sqrt(50) , CA = sqrt( 45)
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AB^2 + CA^2 = BC ^2
done
u got the answer Purple.
(2,1) (4,0)= sqrt5 (4,0) (5,7) = 5sqrt 2 (2,1) (5,7) = 3sqrt5
best to not simplify them
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because then youn can automatically that 5 +45 = 50
can see*
oh ok...
Yeah, same here. I also dont simply them! ^.^
thanks SAIFOO AND ELECE!
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uw.
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