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Mathematics 16 Online
OpenStudy (anonymous):

I am confused with this formula in Arithmetic progression (AKA Series) State the values of a and in each of the following and find Sn as indicated. 7 + 3 - 1 - 5 - . . ..., S20 Using Sn = N/2 ( 2a +(n-1)d I know a = 7 d= -4 L= S20

OpenStudy (anonymous):

so then plug in your values for n=20

OpenStudy (anonymous):

It gives me - 620, I am not sure is right!

OpenStudy (anonymous):

Entered as 20/2 ( 2x7 + (20-1) -4 = -620

OpenStudy (anonymous):

that's correct. you can check your calculations by manually adding the series, since you know that each term is just the previous term -4.

OpenStudy (anonymous):

doing this on a calculator you can see that S(20) is -620

OpenStudy (anonymous):

Isn't it just 7-4n?

OpenStudy (anonymous):

Ignore me, I haven't woke up yet...

OpenStudy (anonymous):

@estudier I did that first but I was told it was the other formula, otherwise the answer would had ben - 69. Thanks Napervillian!

OpenStudy (anonymous):

no prob! the other formula uses the geometric series trick, it's a good one to learn.

OpenStudy (anonymous):

nvm. it's not geometric sequence. i've been up way too late tonight.

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