Given f(2)=4 and f'(2)=-5 find the equation of the tangent line at x=2
y - 2 = -5(x-4)
Slope is the tangent line which is the first derivative..
shouldnt you switch the 2 and the 4?
please show working lol thanks
oh yea sorry...
or am i tired?
y=mx+b m=f'(2)=-5 y=-5x+b x=2 y=4 4=-5*2+b 14=b so y=-5x+14
you're right joemath lol i just woke up haha..
because your crazy smart you made me second guess myself lolol
thanks joe! myininaya and bahroom!
Here's the deal purple: f ' (x) = slope f ( x ) = y So you have a point: (x,y); in your case (2,4) slope, m = f ' (2) = -5 y-y1 = M(x-x1) y-4=-5(x-2)
and bahrom* go get some cofee thanks
lol haha.. i will..
LOL
i want a java chip frapaccino so bad!
lol...myinaya i could use a caramel frap from starbucks
you need to try the java chip
i can never remember the name of what i get, i add peppermint to it though <.<
lol...java chip probably isnt in my area im out guys thanks for your help!
later
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