find f(g(x)) and g(f(x)) and determine wether the pair of functions f and g are inverse of each other. f(x)=8x+8 and g(x)=x-8/8 f(g(x))=
\[f(x)=8x+8, g(x)=\frac{x-8}{8}\] \[f(g(x))=f(\frac{x-8}{8})=8(\frac{x-8}{8})+8=x-8+8=x+0=x\] \[g(f(x))=g(8x+8)=\frac{(8x+8)-8}{8}=\frac{8x}{8}=x\] f and g are inverses of each other
You do the "inside first" so you the value of g(x) into the function (f(x) And vice versa for the other one. Do you understand?
you can also try it with numbers to get an idea of what is going on \[f(2)=8\times 2+8=16+8=24\] \[g(24)=\frac{24-8}{8}=\frac{16}{8}=2\]
any questions?
so if f sends 2 to 24, g sends 24 to 2 and do on
x is a number lol
well you could try it with \[\pi\]
or \[e^\pi\]
show off
btw you know from elementary algebra that if you want to solve \[8x+8=24\] for x, you would do the following steps: a) subtract 8 b) divide by 2 that is what the inverse function says to do
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