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solve the inequality (2x+15)/x < x
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where did u get x^3?
2x+15x<x*2 x*2 -17x >0 x(x-17) >0
2x+15<x^2 <=> x^2-2x-15>0 D=4+60=64 x1=6 x2=-2
I am not sure,sorry If I wrong.
thx for all ur help y'alls
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my mistake, I typed it in wrong. 15/x+2<x
Do you want me yo continue or you are okay?
here is your answer...
when x>17
so i did (2x+15) < x^2
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@jhonyy9 where did you find the 15x ?
Hi Alexix, The procedure is right. But there is a small mistake in the first step. The inequality, gives two possible answers based on the sign of x. \[(2x+15)/x<x\] The work given by you is correct for x>0. But for x<0, you get another solution which is \[(2x+15)/x<x\Rightarrow 2x+15>x^2\]
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