Question

Mary has $3.00 in nickels, dimes, and quarters. If she has twice as many dimes as quarters and twenty-seven more nickels than dimes, how many coins of each type does she have?

Answer 1

x+y+z=3
y=2z
x=y+27
solve this

Answer 2

and it comes out to 3 seperate answers?

Answer 3

i need to know how many quarters, dimes, and nickels she has left of each

Answer 4

how many of each type she has*

Answer 5

here d+n+q=3
2d=q
27+d=n
now you can solve, by substituting

Answer 6

plug in the value for q, and n in terms of d into the d+n+q equation, you will get the number of d/dimes. than plug that number in to the two other equations to get the number of q/quarters and n/nickels

Answer 7

what does it come out to?

Answer 8

i cant figure out how to do it based on what you are saying

Answer 9

ok just tell me what q is someone. i will solve the rest i just need one variable if no one can let me check them and answer by answering them all

Answer 10

ok fixed this\[0.10d + 0.05n +0.25q = 3.00\]

2d=q

27+n = d

\[0.10d + 0.05(27+d) +0.25(2d) = 3.00\]
\[(0.10+0.05+0.50)d +1.35=3.00\]

Answer 11

\[(0.10+0.05+0.50)d = 1.65\]

Answer 12

solve for d, sorry i don't have a calculator this will be easier for you to solve

Answer 13

once you have d, plug that value into the two short equations, 2d=q and 27+d = n

Answer 14

so d = .0025 based on whats in the parnetheses. where is the 1.65 from

Answer 15

d should equal 1.65/(0.10+0.05+0.50)

Answer 16

so would be closer to a value of 3, but I may be solving this inaccurately

Answer 17

1.65 from 3.00-1.35

Answer 18

1.65 * .0025 = .004125?

Answer 19

sorry the first equation is:
5x+10y+25z=300

y=2z
x=y+27

solution:
x=33
y=6
z=3

33 nickels, 6 dimes and 3 quarters

Answer 20

THANKYOU

Answer 21

easier to use whole numbers instead of decimals, but you should be able to get same answers

Answer 22

i don't live in U. S. so i didn't know the value in cents of nickels, dimes and quarters