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solve: (1/625)=5^x
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5^(x+4) = 1
\[625^{-1}=5^x\]\[5^{-4}=5^x\]x=-4
that's right... sorry... little rusty :S
are you using logs?
what are logs?
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nah i used indices method
cus if you are they probably want you to do it a different way then that... if you take the log of both sides its easy to get the x out of the exponent.
but if you arnt using them its too hard to explain all the log rules on this... so just use the above method.
using logs it would be something like this 1. ln(1/625)=ln(5^x): ln(1/625)=xln(5) 2. x=ln(1/625)/ln(5) 3.x=-4
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