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Mathematics 16 Online
OpenStudy (anonymous):

solve: (1/625)=5^x

OpenStudy (anonymous):

5^(x+4) = 1

OpenStudy (anonymous):

\[625^{-1}=5^x\]\[5^{-4}=5^x\]x=-4

OpenStudy (anonymous):

that's right... sorry... little rusty :S

OpenStudy (anonymous):

are you using logs?

OpenStudy (anonymous):

what are logs?

OpenStudy (anonymous):

nah i used indices method

OpenStudy (anonymous):

cus if you are they probably want you to do it a different way then that... if you take the log of both sides its easy to get the x out of the exponent.

OpenStudy (anonymous):

but if you arnt using them its too hard to explain all the log rules on this... so just use the above method.

OpenStudy (anonymous):

using logs it would be something like this 1. ln(1/625)=ln(5^x): ln(1/625)=xln(5) 2. x=ln(1/625)/ln(5) 3.x=-4

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