How would you graph a circle with the equation x^2 + y^2 + 4x - 10y + 13 = 0?

Question

anonymous · Answer

completing squares

anonymous · Answer

http://www.wolframalpha.com/input/?i=x^2+%2B+y^2+%2B+4x+-+10y+%2B+13+%3D+0

anonymous · Answer

Ok so I have (x^2 - 4X     ) + (y^2 - 10y   )= -13? I am stuck on what to fill in the blanks in both parentheses with...

anonymous · Answer

To complete squares you wan the expression that squares to give the expressions you have in the brackets above so

(x-2)^2  will give us the x^2 and 4x terms but also give us a 4 which we don't want so we have to take it out (subtract it).

You do the same thing with the y^2.

You end up with (x-2)^2 -4 +(y-5)^2 -25 = -13 and then bring all the integers over to rhs

 (x-2)^2 + (y-5)^2 = -13 +29 = 16 = 4^2 which is in standard form.