Find the linear function f(x) such that f(2)=-3 and f(6)=-5.
f(x)=0.5x-2
that doesn't work.
f(x)=0.5x-2 works...
sorry
no problem. nothing to be sorry about! :)
I worked it by finding the slope, and then substituting the values given in y = mx+c
Hes right, it doesnt work.
Would any of you mind showing me how you got there? Thanks :-)
the correct answer is f(x)=-1/2x-2 but I don't know how to get there.
go with what mandar suggested
elizated forgot to add the negative sign in his equation
Since it's a linear equation, the equation is a straight line. The points given are (2, -3) and (6, -5) Find the slope, and use y = mx+c -> f(x) = -0.5x +c Find c using the values given in the problem statement.
well set up an x y chart: x | y 0 - 1 - 2 -3 3 - 4 - 5 - 6 -5 then start filling in the missing numbers probably starting with 4: -4. since it's counting by 0.5, that's your slope. now wor back to zero and that's your y intercept.
woops, sorry it is negative. and i'm a girl by the way...
Thank you very much!
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