Question

I had this problem, (3x^-1/4y^-1)^-2 and i get a fraction within a fraction within a fraction and i am having trouble simplifying the ^ means raised to the power of,,, please help

Answer 1

first invert it because its a negative power
then square both denomniator and numerator

Answer 2

\[(\frac{4y^{-1}}{3x^{-1}})^2\]
that 2 is suppose to be an exponent
this should help

Answer 3

so its the same as 1/((3y/4x)^2)

Answer 4

\[(\frac{4x}{3y})^2\]

Answer 5

\[\frac{16x^2}{9y^2}\]

Answer 6

(16 x^2)/(9 y^2)

Answer 7

(9y^2)/(16x^2) is the correct answer because in the original problem its all to the power of -2 which means its flipped

Answer 8

rocket ur answer is wrong unless he wrote it wrong

Answer 9

x^-1 is the same as 1/x

Answer 10

rockets answer would be right if we had
((3y)^(-1))/((4x)^(-1)))^(-2)

Answer 11

i thought that is what we had myininaya

Answer 12

\[(4y ^{-1}\div3x ^{-1})^{2} \]

Answer 13

rocket science is correct it is just based on rule of indices

Answer 14

how do you remember the negitives from that?

Answer 15

ok i was looking in the original post, I had this problem, (3x^-1/4y^-1)^-2 and i get a fraction within a fraction within a fraction and i am having trouble simplifying the ^ means raised to the power of,,, please help.

Answer 16

ok maybe this would look prettier to you\[(\frac{3x^{-1}}{4y^{-1}})^{-2}=\frac{3^{-2}x^{2}}{4^{-2}y^{2}}=\frac{16x^2}{9y^2}\]

Answer 17

is this better looking?

Answer 18

ok i was looking in the original post, I had this problem, (3x^-1/4y^-1)^-2 and i get a fraction within a fraction within a fraction and i am having trouble simplifying the ^ means raised to the power of,,, please help.

Answer 19

thank you guys, I get it now

Answer 20

i will put one more step in
\[\frac{4^2x^2}{3^2y^2}=\frac{16x^2}{9y^2}\]

Answer 21

thank you