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2cos2n@+1/2cos@+1=(2cos@-1)(2cos@-1)(2cos2square@-1).. (2cos2n-1@-1).prove it..
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having a hard time understanding, is this the question: \[\frac{2\cos(2n\theta+1)}{2\cos(\theta)} = \cdots\] im not even sure what the right hand side is....
oh oh, maybe: \[2\cos^{2n}(\theta+1) \] instead?
hey shruti can you write this using the equation thingy below if you want you can use frac{somethin}{something} to enter in fractions
or maybe scan or take a picture and upload it.
that might be easier
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dont know what it is exactly , but pretty good chance it involves complex numbers and sum of a gp
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