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Test the series for convergence or divergence. Say if convergence is conditional \[\sum_{2}^{\infty}\left( \left( -1 \right)^{n +1}n \right)\div \left( 4n ^{2}+1 \right)\]
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its the sum from one to infty sorry \[\sum_{1}^{\infty}\]
The series converges by the alternating series test (to around 0.129032) but does not converge absolutely by the integral test.
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