Question

Differential equation.(see attachment)
Second part only.

Answer 1

sub w = v'
w' = v''
take integrating factor of e^(t/RC)

Vo = Ae^-(t/RC) + B

Answer 2

2nd part basically says Vo(0) = 0 and Vo'(0) = 1
take deriv of the general soln i posted above, and plug in and the same for the general to solve for A and B

Answer 3

Vo' = - A * e^(-t/RC)/RC
Vo'(0) = 1 = * A * e^0 / RC
A = -RC
Vo(0) = 0 = -RC * e ^0 + B = 0
B = RC

Vo = (-e^-(t/RC) + 1)* RC

TADA! Mathematics

Answer 4

Thank you very much !!!

Answer 5

np :3