Find the value of Q in the following system so that the solution to the system is
{(x,y) : x-3y=4}
x-3y=4, 2x+qy=8

Question

Find the value of Q in the following system so that the solution to the system is
 {(x,y) : x-3y=4}
x-3y=4, 2x+qy=8

anonymous · Answer

Q = -6

anonymous · Answer

1) First eqation
x-3y=4

2) 2x+qy=8
 
It looks like if first equations is multiplied by 2 we get second equation, So let do it
2x-6y=8

So we see that in place of q is -6

anonymous · Answer

Where do you see a,b,or c

anonymous · Answer

x = 4+ 3y Thus...

2(4 +3y) + qy = 8 
8 + 6y + qy = 8
6y +qy = 0
qy = -6y
q = -6

anonymous · Answer

i dont that one girl said it the way it is supposed to be written but everytime i do it it gets messed up is like this

Find the value of Q in the following system so that the solution to the system is 
{(x,y) : x-3y=4} 
x-3y=4 
2x+qy=8

anonymous · Answer

{(x,y) : x-3y=4}

 x-3y=4

 2x+qy=8

anonymous · Answer

Kassia did that help?

anonymous · Answer

yeah so the answer is definetly -6?