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Mathematics 16 Online
OpenStudy (anonymous):

Find dy if y=(e^x)logx

OpenStudy (anonymous):

go get'em cowboy

OpenStudy (anonymous):

i assume this means \[\frac{d}{dx}e^x \ln(x)\] but i could be wrong

OpenStudy (anonymous):

it says log, not natural log, so I assume its log of ten, so ln...

OpenStudy (dumbcow):

Use product rule \[dy = \frac{d}{dx}e^{x}*\log x + e^{x}*\frac{d}{dx}\log x\] \[dy = e^{x}\log x + \frac{e^{x}}{x} \]

OpenStudy (dumbcow):

wait i assumed natural log

OpenStudy (anonymous):

if it is \[\log_{10}(x)\] the the derivative is \[\frac{\ln(10)}{x}\]

OpenStudy (dumbcow):

yep

OpenStudy (anonymous):

right. ok thanks.

OpenStudy (dumbcow):

your welcome :)

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