Question

My problem is asking to solve the linear system by using substitution. the problem:
4x+3y=0 2x+y=-2

Answer 1

Simple. Solve one equation for one of the variables. Substitute your result into the other equation and solve.

Answer 2

rearrange second

y= -2x-2

sub into first

4x +3 ( -2x-2) =0

-2x -6 =0

x=-3

sub back inot first

y= 4

x=-3, y=4

Answer 3

So, solving equation 2 for y gives y = -2x-2. Substitute for y in the first to get 4x + 3(-2x-2) = 0, so 4x - 6x -6 = 0, so -2x = 6, so x = -3.

Answer 4

Then substitute -3 for x in either equation and solve for y.

Answer 5

okayy. Got you. Thanx.