Question

Another question! Whoo. So, this picture:
https://courses.vlacs.org/vlacontent/algebra2_v10_gs//assessments-xml/res0012/prac_g_03.gif%22

What inequality is graphed? Also, could you show me HOW I find that equation to go along with it? Thanks so much.

Answer 1

Is that in equality question with absolute value too?

Answer 2

If it is,|x-h|+k
let see where the vertex is from the picture

look to me like (1.5,1)

Answer 3

-nodnod- I can see that, yep.

Answer 4

so
y=-|x-1.5|+1
But remember this is inequality
since it is shaded down--> less than
y<-|x-1.5|+1

Answer 5

-nodnod- Alright :] I see.

Answer 6

Alright. Thank you so much! :D You're amazing <3

Answer 7

You are welcome

Answer 8

wait, that can't be it.

Answer 9

the answers are this:

Answer 10

a. y > - |2x + 3| - 1
b. y < |x + 3| + 1
c. y < - |2x - 3| + 1
d. y < |2x - 3| - 1

Answer 11

It's a mult choice, and that's not a choice :/

Answer 12

Oh, they care about slope, Okay, no problem

Let's find a slope of the line.

To do that , let's choose two points

Answer 13

Two points I chose
(1.5,1)(2.5,-1)
Looks to me like -2/1 =-2

Answer 14

Alright :] I follow you.

Answer 15

Yep, so far, so good!

Answer 16

From slope we get
y<|-2x+A|+1
Since it is facing down, stick negative in front
y<-|-2x+A|+1
Remember Vertex formula is
|(x-h)|+k

But we don't have (x-h) instead we have (-2x-A); so we try to get it into form
-2(x+A/2)

From that we have see h=A/2 ; since h is 1.5 , A must be twice as much so 3

Now that we know what A is let plug back into following equation

y<-|-2x+A|+1
y<-|-2x+3|+1
distribute the negative
y<-|2x-3|+1

Answer 17

Alright! Thanks :D Yay.

Answer 18

Proof

http://tinyurl.com/3bpve8l

Answer 19

You are a beautiful person.