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2lnx-1/2/e^x=0
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\[2 \ln (x)-\frac{e^x}{2}=0\] Is this right?
unsolvable
\[2lnx-1\]/\[2-e^x\]
i can give you an iteration,
is this what you have written? \[\frac{2lnx-1}{2-e^x}=0\] \[2lnx-1=0\] \[2lnx=1\] \[lnx=\frac{1}{2}\] \[x=e^\frac{1}{2}\]
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