Question

solve this by the addition method
3x+2y=-3
2x+3y=-2

Answer 1

1) Multiply one of the equations by -1, therefore you get:
3x+2y=-3
-2x- 3y= 2
-----------
x - y = -1

2) Solve for x in terms of y
x = y - 1

3) Substitute back into either equation
3(y-1) + 2y=-3

4) Solve for y
y = 0

5) Substitute back into the other equation
-2x-3(0) = 2

6) Solve for x
x = -1

Answer 2

Is that the addition method, don't know, I am asking?

Answer 3

You need to multiply the first equation by 2 and the second equation by 3 to start.

6x + 4y = -6
6x + 9y = -6
========= Subtract
0x + -5y = 0
dividing through results in y = 0

substitute that value of y in to either equation to get x = -1

Answer 4

Sorry, thought you said subtraction method. Just multiply the second equation by -3 instead.

6x + 4y = -6
-6x - 9y = 6
========== Add
0x - 5y = 0

etc.

Answer 5

Hmm, a subtraction method...