Question

what are both solutions for the quadratic equation below:
3x^2 - 5x - 1 = 0

Answer 1

use the quadratic formula

Answer 2

i know the formula i just confuse myself while applying it.

Answer 3

a=,b=-5,c=-1
\[x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}=\frac{-(-5) \pm \sqrt{(-5)^2-4(3)(-1)}}{2(3)}\]

Answer 4

\[x=\frac{5 \pm \sqrt{25+12}}{6}=\frac{5 \pm \sqrt{37}}{6}\]

Answer 5

What do i do about the plus/minus symbol. idk how to use it

Answer 6

you have solutions
one with the +
and one with the -

Answer 7

thannk you:)

Answer 8

\[\frac{5 \pm \sqrt{37}}{6}\]
is the same as saying:
\[\frac{5+\sqrt{37}}{6}. \frac{5-\sqrt{37}}{6}\]