If y=2xsquared+7x-2/xsquared-25 find horizontal asymptotes
is it: \[y=(2x ^{2}+7x-2)/(x ^{2}-25)\] ?
yes!
The horizontal asymptote tells me, roughly, where the graph will go when x is really, really big...or other : A horizontal asymptote is a y-value which a function approaches but does not actually reach. Horizontal asymptotes take place as the graph of the function extends forever to the left or to the right. By this, I mean we are looking for very large positive or negative values of x.
We need to figure out what this fraction approaches as x gets huge. To do that, we'll pick the "dominant" terms in the numberator and denominator. Dominant terms are those with the largest exponents. As x goes to infinity, the other terms are essentially meaningless. The exponents in this case are the same in the numerator and denominator. See it? The dominant terms in each have an exponent of 2. Get rid of the other terms and you're left with: f(x)=2x^2/x^2=2 In this case, 2 is the horizontal asymptote of the above function.
Ok, from there?
? that should be the answer horizontal asymptote : y=2
Oh, that is the answer!!
You are so good!! YOu are so helpful!
God bless you!!
i think this may help - see attached graph of you function. blessing to you too!
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