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Mathematics 21 Online
OpenStudy (anonymous):

does g(x)2x^2-x = 2x^2-x+a+h?

OpenStudy (anonymous):

are A and H constants?

OpenStudy (anonymous):

constant?

OpenStudy (anonymous):

we do not know

OpenStudy (anonymous):

it says find g(a+h) we do not know if that is even the right answer

OpenStudy (anonymous):

could it be a^2 +h^2?

OpenStudy (anonymous):

well all you do is subsitute a+h into all x So g(a+h) = 2(a+h)^2 - a - h

OpenStudy (anonymous):

that is the answer?

OpenStudy (anonymous):

oh, thank you so much!! GOD bless you<><

OpenStudy (anonymous):

well from what you told me, i believe so ha.

OpenStudy (anonymous):

Well, it worked it out so thank you!

OpenStudy (anonymous):

GOD bless<><

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