graph the function 4/x^2+5X+4 1. where is the symmetry 2. y int: 3.x int: 4. y cordinate of the horizontal retricemptote 5.x cordinate of the horizontal retricemptote
please help
the question is not clear. rewrite it using brackets
(4)/(x^2+5x+4)
Using y = ax^2 + bx + c that is in this example a = 1, b = 5 and c = 4 find the axis of symmetry using the formula x =-b/2a. Draw an x and y axis then draw a vertical dotted line for where you found your axis of symmetry.
You're going to have to find the y value that goes with this x axis of symmetry value. Plug it into the equation. TADA! You should have the coordinate of the vertex! Now choose values of x either side of your axis of symmetry, two x values either side of the axis of symmetry is ideal. Plug those values into your equation to find the y values. Plot all these points, join the "dots" that is coordinates, draw arrows to show that this function continues.
To find the x and y intercepts, plug in x = 0 for the y intercept and plug in y = 0 for the x intercept.
Finally, an asymptote is a straight line that a curve/equation/function won't cross - kinda like a line with cooties ;) Can you see where the graph has any invisible lines where it just won't cross? I'll give you a hint:- the graph has no vertical asymptotes but there sure is a horizontal one.
Join our real-time social learning platform and learn together with your friends!