Bonnie has one alloy containing 23% aluminum and another containing 45% aluminum. How many pounds of each alloy must he use to make 58 pounds of a third alloy containing 42% aluminum?
You can work this out using a system of equations. x represents the pounds of alloy 1 y represents the pounds of alloy 2 x + y = 58 (the number of pounds of each allow to make 58 pounds) 0.23x + 0.45y = 0.42 x 58 (the amount of aluminum in the first, second and resulting alloy.
The second equation is easier to work with if you multiply through by 100 to get rid of the decimals. In other words, 23x + 45y = 2436 From the first equation x = 58 - y Substitute that into the second equation and you will find your answer. Don't forget to check the answer. It ends up being a decimal.
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