A baseball player hits a ball. The ball leaves the bat with an initial upward velocity of 35 meters per second. If the ball is 1 meter off the ground when it leaves the bat, about how many seconds will it take for the ball to hit the ground?
i hate these
speed = distance over time.
thats nt the answer
ah now we have a problem!
hmm
was it hit vertically up in the air?
do you know what formula to use?
7 seconds -0.03 seconds 14.34 seconds 35.133 seconds
its one of those
0.03 (not in nedative)
(negative)
uhh negatie is the only one
you have to use the formula for free fall
wtf idk how thats why im asking u guys lol
do you have an example for another problem with a solution?
no
i know it in feet. myininaya knows it in meters
i think it is \[-4.9t^2\] yes?
in meters that is. so you have to solve \[1+35t-4.9t^2=0\] for t. lets see mr khan do that in two seconds
in any case i think you get 7
finally i got one!
.3s
Vy= dy/ t . solve for t.. t= dy/Vy, amnd thus 1/35, seconds cancel out, .3m
wouldn't you need to know the initial upward acceleration of the ball at the moment it left the bat?
let me get my physics referance table, is 1m its max height
oh, you are right. ignore my posts.
these problems are nonsense don't take them seriously
they are pretending that the ball goes straight up in the air. the whole exercise is pointless
and so to all a \[\huge{\color{red}{goodnight!}}\]
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