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What is the perimeter of a square with a diagonal of 3√2?
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3 , 12, or 18
12
thank u!
12
If you use Pythagorean Theorum the hypotenuse squared is going to equal the squares of the other two sides (which are equal). So, (3√2)^2 = x^2 + x^2 9(2) = 2x^2 18 = 2x^2 9 = x^2 3 = x, so each side is 3 units long. A square has four sides, so the perimeter is 3 x 4 or 12 units in length.
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